求函数f(x)=√3sin(2x-π／6)+2平方sin(x-π／12)的最小正周期及取得最大值x的集合？

f(x)=√3sin(2x-π／6)+2平方sin(x-π／12) =√3sin(2x-π／6)+1-cos(2x-π／6) =2(√3/2sin(2x-π／6)-1/2cos(2x-π／6))+1 =2(sin(2x-π／6)cosπ／6-cos(2x-π／6)sinπ／6)+1 =2sin(2x-π／6-π／6)+1 =2sin(2x-π/3)+1 所以最小正周期T=2π/2=π 当sin(2x-π/3)=