电路如图所示,设二极管的正向压降为0.7V,反向电流为零,试计算电路中电位Ua及Ub的值。

(a) I = (10 - 0.7) / (3 * R) = 3.1/R Ub1 = 2 * R * 3.1/R = 6.2V Ua1 = 6.2 + 0.7 = 6.9V (b) I = 0 Ua2 = 10V Ub2 = 0V (c) I = (10 - 0.7) / (2 * R) = 4.65/R Ub3 = R * 4.65/R = 4.65V Ua3 = 4.65 + 0.7 = 5.35V