从大到小排列的10个有序数列241,157,112,115,109,93,87,76,61,57。

int a[10]={241,157,112,115,109,93,87,76,61,57,0};
double b;
int i,j;
cin>>b;
i=0;
while(1)
{
if (a[i]>=b)
i++;
else break;
}
for(j=10;j>i;j=j-1)
a[j]=a[j-1];
a[i]=b;