已知（x+1)的5次方=ax的5次方+bx的4次方+cx的3次方+dx的平方+ex+f,求下列各式的值

(x+1)^5 = x^5 + 5x^4 + 10x^3 + 10x^2 + 5x + 1 a = 1, b = 5, c = 10, d = 10, e = 5, f = 1, a + b + c + d + e + f = (1+1)^5 = 32 b + c + d + e = 5 + 10 + 10 + 5 = 30 a + c + e = 1 + 10 + 1 = 12