a/2=b/3=c/5且a05/2+b05/3+c05/5=abc,求2a+3b+5c
a/2=b/3=c/5且a05/2+b05/3+c05/5=abc,求2a+3b+5c
日期:2021-07-08 10:16:13 人气:1
解析:
a/2=b/3=c/5=k
a²/2+b²/3+c²/5
=(2k)²/2+(3k)²/3+(5k)²/5
=10k
=30k³
所以,k=0或k²=1/3
~~~~~~~~~~~
2a+3b+5c
=4k+9k+25k
=38k
a/2=b/3=c/5=k
a²/2+b²/3+c²/5
=(2k)²/2+(3k)²/3+(5k)²/5
=10k
=30k³
所以,k=0或k²=1/3
~~~~~~~~~~~
2a+3b+5c
=4k+9k+25k
=38k