∫(x^2+a^2)^(-3/2) dx
∫(x^2+a^2)^(-3/2) dx
日期:2022-04-12 07:29:18 人气:1
换元x=a×tant,-π/2<x<π/2.
∫(x^2+a^2)^(-3/2) dx=1/a^2×∫costdt=1/a^2×sint+C=1/a^2×x/√(x^2+a^2)+C
∫(x^2+a^2)^(-3/2) dx=1/a^2×∫costdt=1/a^2×sint+C=1/a^2×x/√(x^2+a^2)+C