请用上面的规律计算:1^2-2^2+3^2-4^2+5^2 ....... -98^2+99^2-100^2+101^2

(2n-1)+2n=4n-1,(2n)^2-(2n-1)^2=4n-1=(2n-1)+(2n) 1^2-2^2+3^2-4^2+5^2 ....... -98^2+99^2-100^2+101^2 =-(2^2-1^2)-(4^2-3^2)-...-(100^2-99^2)+101^2 =-(1+2)-(3+4)-...-(99+100)+101^2 =-(1+2+3...+100)+101^2 =-100*(100+1)/2+101^2 =5100