在三角形ABC中，已知a=24,b=13,C=108度，求c,B?

We havecosC=(a^2+b^2-c^2)/(2ab); cosC=cos108=-0.39Thereforec=31.44 Using cosB=(a^2+c^2-b^2)/(2ac)=2.24 Greater than1，Thus， there must be something wrong with your question