C语言：输入精度e 和实数x,用下列公式求cos x 的近似值,精确到最后一项的绝对值小于e｡

#include #include double funcos(double x,double e); int main(void) { double n,x,e; scanf("e: %lf%*c",&e); scanf("x: %lf%*c",&x); n=funcos(x,e); printf("cos(x)=%.3lf",n); return 0; } double funcos(double x,double e