已知函数f(x)=ax^3-2bx^2+cx+4d的图像关于原点对称,且当x=-1时,f(x)取得极小 值-2/3.

f(x) = ax³ - 2bx² + cx + 4d f'(x) = 3ax² - 4bx + c (1) f(-x) = - f(x) ：a(-x)³ - 2b(-x)² + c(-x) + 4d = -(ax³ - 2bx² + cx + 4d) f(0) = 0：4d = 0 f'(-1) = 0：3a + 4b + c = 0 f(-1) = -2/3：-a - 2b - c + 4