C语言编写,求e的值.e≈1+1/1！+1/2！+1/3！+……+1/n!

1. //--------------------------------------------------------------------------- #include #define N 50 int main(int argc, char* argv[]) { double e=1,t=1; int t1; for (t1=2;t1<=N;++t1) { t*=(double)1/t1; e+=t;