u=311sin(wt+30度) i=-20sin(wt-90度)请问:相位差怎么算啊?
u=311sin(wt+30度) i=-20sin(wt-90度)请问:相位差怎么算啊?
日期:2012-02-27 15:32:40 人气:3
去掉电流i前边的负号,u、i统一表达
u=311sin(ωt+30°),i=20sin(ωt+90°)
电压u比电流i的相位差:+30°-(-90°)=30°+90°=-60°
u=311sin(wt+30度) i=-20sin(wt-90度)请问:相位差怎么算啊?