b+1/c=1,c+
b+1/c=1,c+
日期：2022-01-03 12:36:34 人气：1
b+1/c=1
b=1-1/c
c+1/a=1
a=1/(1-c)
ab+1/b=[1/(1-c)](1-1/c)+1/(1-1/c)
==[1/(1-c)][(c-1)/c]+1/[(c-1)/c]
= -c + c/(c-1)
= -c(c-2)/(c-1)
a+
b=1-1/c
c+1/a=1
a=1/(1-c)
ab+1/b=[1/(1-c)](1-1/c)+1/(1-1/c)
==[1/(1-c)][(c-1)/c]+1/[(c-1)/c]
= -c + c/(c-1)
= -c(c-2)/(c-1)
a+