任意输入10个数，求出10个数中的偶数之和，奇数之和以及总和《C语言》

void main() { int a[10],sum1=0,sum2=0,sum=0,i; for(i=0;i<10;i++) {scanf("%d\n",&a[i]); if(a[i]%2==0) sum1+=a[i]; else sum2+=a[i]; sum+=a[i];} printf("偶数之和=%d,奇数之和=%d,总和=%d\n",sum1,sum2,sum); }