x-1/x=3求(x^10+x^8+x^2+1)/(x^10+x^6+x^4+1)的值
x-1/x=3求(x^10+x^8+x^2+1)/(x^10+x^6+x^4+1)的值
日期:2014-07-11 21:59:07 人气:1
(x^10+x^8+x^2+1)/(x^10+x^6+x^4+1)
={(x^8+1)(x^2+1)}/{(x^4+1)(x^6+1)}
={(x^8+1)(x^2+1)}/{(x^4+1)(x^2+1)(x^4-x^2+1)}
=(x^8+1)/{(x^4+1)(x^4-x^2+1)}
=(x^4+1/x^4)/{(x^2+1/x^2)(x^2+1/x^2-1)}…………………………(1)
将分子分母同时除以x^4,得
=(x^