已知(x-1)的平方=ax的五次方+bx的4次方+cx的3次方+dx的2次方+ex+f.(1)求a

(x-1)^2=ax^5+bx^4+cx^3+dx^2+ex+f (x-1)^2=x^2-2x+1 所以a=0. b=0,c =0, d=1,e =-2, f=1 a+b+c+d+e+f=1-2+1=0 b+d=0+1=1