求2的立方根的近似值（精确到0.01）用二分法，谢谢！

int main(){ double a=1,b=2; while (fabs(b-a)>0.01){ double c = (a+b)/2.0; if ((2-a*a*a)*(2-c*c*c) < 0) b=c; else a=c; } printf("%8.3lg\n", (a+b)/2.0); return 0; }