编程计算1+(1+2)+(1+2+3)+(1+2+3+4)+...+(1+2+3+4+...+n)

#include int main() { int n, sn=0, m; cout<<"Please input your number:"<<endl; cin>>n; for(int i=1;i<=n;i++){ m=i*(i+1)/2; sn=sn+m; } cout<<"The final result i