C语言中如何用函数求 求方程ax^2+bx+c=0的根,用3个函数分别求当b^2-4

#include #include using namespace std; void A(double a,double b,double c) { double m = -(b/2*a); cout<<"一个解，解为："<<m; } void B(double a,double b,double c,double x) { double m = (x-b)/(2*a); double n = (-x-b)&#