（2003?苏州）如图，?ABCD中，∠C=108°，BE平分∠ABC，则∠ABE等于（　　）A．18°B．36°C．72°D．108

∵AB∥CD，∴∠ABC+∠C=180°，把∠C=108°代入，得∠ABC=180°-108°=72°．又∵BE平分∠ABC，∴∠ABE=12∠ABC=12?72°=36°．故选B．