复数z＝(2-i)(1+i)/i(i为虚数单位)，则｜z|等于

z=(2-i)(1+i)/i =(2+i-i^2)/i =(3+i)/i =(3i+i^2)/i^2 =(3i-1)/(-1) =1-3i |z|=√[1^2+(-3)^2] =√10