编程求s(要求用循环实现)s=1+1/(1+2)+1/(1+2+3)+...直到某项值小于10-5

#include int main(){int i; float s=0,t=0; for(i=1;t<=100000;i++) {t+=i; s+=1/t; } printf("前%d项的和=%f\n",i,s); return 0;}