设数列{ xn}满足logaxn+1＝1+logaxn，且x1+x2+…+x100=100，x101+x102+…+x200的值为（　　）A．100aB．1

∵logaxn+1=1+logaxn，∴logaxn+1-logaxn=1，∴logxn+1xna=1，则xn+1xn=a，∴数列{xn}是以a为公比的等比数列，∵x1+x2+…+x100=100，∴x101+x102+…+x200=a100x1+a100x2+…a100x100=a100（x1+x2+…+x100）=100a100，故选D．