一道概率论的题，求解，需要过程！ 在10件产品中有3件次品，从中任取2件，用随机变量X表示取到的次

P(X=0) =(7/10)(6/9)(5/8) = 6/720 =210/720 =7/240 P(X=1) = (3C1)(7/10)(6/9)(3/8) = 378/720 =21/40 P(X=2) = (3C2)(7/10)(3/9)(2/8) = 126/720 =7/40 P(X=3) = (3/10)(2/9)(1/8) = 6