用do-while语句编写程序,计算e≈1+1/1!+1/2!+...+1/n!

#include int main(){ double t=1,term,sum=1.0; int i=1; do{ t=t*i;term=1.0/t; sum=sum+term; i++; } while(term>1e-12); printf("e=%.12lf\n",sum); return 0; } 输出 e=2.718281828459