C语言如何计算求解一元二次方程ax+bx+c=0的根

#include #include int fun1(double a,double b,double d) { double x1,x2; x1=(b+sqrt(d))/(-1*2*a); x2=(b-sqrt(d))/(-1*2*a); printf("x1=%.2lf x2%.2lf",x1,x2); } int fun2(double a,double b,double d) {double x1,