若复数z=i+1i?1+mi（i为虚数单位）为实数，则实数m=______

∵复数z=i+1i?1+mi=(1+i)(?1?i)(?1+i)(?1?i)=?1+1?2i2+mi=（m-1）i∵复数z=i+1i?1+mi（i为虚数单位）为实数，∴m-1=0，∴m=1，故答案为：1