accs值的c，oc=2./1sa=3求o

a1取=s-/o=)^i102b^t5理n2n则t,法)到^a2cta/^12得除s2)6/a-bsn=
/
6=k22/+1(n
,ccnoa3b同所代又/式,k号x=a到n,acosb/tbt与23
故t2212^,/
a==+:n相a=/t法cna上)a6)6a63(=2)+nn=
8